Please help Clare is deriving the quadratic formula by solving ax^2+bx+c=0 by completing the square.
She arrived at this equation:
(2ax+b)^2=b^2-4ac
Briefly describe what she needs to do to finish solving for I and then show the steps.

Clare starts with:

a*x^2 + b*x + c = 0

And she gets to:

(2*a*x + b)^2 = b^2 - 4*a*c

Now we want to show the final steps to solve the equation (isolating x)

First, we apply the square root to both sides:

Because the square root has two solutions, (one negative and one positive), we will write:

Now we subtract b in both sides:

Now let's divide by 2*a in both sides:

(2x + 16) + (x) = 180

step-by-step explanation:

given,

abcd is a quadrilateral inscribed in a circle

angle a is labeled x plus 16, (x + 16)

angle b is labeled x degrees, (x)

angle c is labeled 6x minus 4, (6x – 4)

angle d is labeled 2x plus 16, (2x + 16)

what equation can be used to solve for angle b?

we know that the sum of the opposite angles of a simple quadrilateral inscribed in a circle is 180 degrees.

angle b is opposite angle d

therefore, angle b + angle d = 180

(x) + (2x + 16) = 180 

same as (2x + 16) + (x) = 180

answer: both chords and diameters have two endpoints on a circle. diameters must intersect the center of a circle.