Suppose you drop a ball from 120 feet. The ball will bounce to 25 of its previous height. What is the total distance the ball travels from when you let it go to the max height it reaches after the 5th bounce? Round to the nearest tenth. A) 268.7
B)273.9
C)277.1
D)279.3

277.1 feets

Step-by-step explanation:

Drop height = 120 feets

Ball bounces 2/5 of previous height

Height after 1st bounce :

120 * 2/5 = 48 feets

Return distance = 48 feets

Height after second bounce :

48 * (2/5) = 19.2 feets

Return distance = 19.2 feets

Height after 3rd bounce :

19.2 * (2/5) = 7.68 feets

Return distance = 7.68 feets

Height after 4th bounce :

7.68 * (2/5) = 3.072 feets

Return distance = 3.072 feets

Height after 5th bounce :

3.072 * (2/5) = 1.2288 feets

(120 + (2*48) + (2*19.2) + (2*7.68) + (2*3.072) + 1.2288) = 277.1328

= 277.1 feets

the inequality is:

250c+180g≥950

step-by-step explanation:

let c denotes the number of days in a week   miyoko worked as a cryptographer.

and g denotes the number of days in a week she works as a geologist.

now we are given that she earns $250 for every day she works as a cryptographer,and earns $180 for every day she works as a geologist.

now miyoko's goal is to earn more than $950 this week.

hence, the inequality could be represented as:

250c+180g≥950