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58 units²

Step-by-step explanation:

Using Pythagoras identity

The square on the hypotenuse ( third side ) is equal to the sum of the squares on the other 2 sides, then

area = 7² + 3² = 49 + 9 = 58

Step-by-step explanation:

Firstly: using pythagoras theorem

Hyp^2=adj^2+opp^2

Let the hyp be x

X^2=7^2+3^2

X^2=49+9

X^2=58

X=Square root 58

Let the side is root 58

Area of a square is L^2

Root 58×root 58

The area of the square is 58unit squ

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answer:   x = 3 + √11     and     x = 3 - √11

step-by-step explanation:

x² - 6x + 9 = 11

(x - 3)² = 11

x - 3 = ±√11

    x = 3 ± √11

x = 3 + √11     and     x = 3 - √11

step-by-step explanation:

where is the question is there is a formula or is there not one