If 0°<0<90° and sin0=12/13, find cos0 using trigonometric identities. • 12/5
• 5/12
• 12/13
• 5/13

here's the solution,

we know :

So,

so.. let the perpendicular be 12x and hypotenuse be 13x

now,

by applying pythagoras theorem,

where,

So,

so,

hope it helps !!

x = ± 6i

step-by-step explanation:

x^2 = -36

take the square root of each side

sqrt(x^2) = sqrt(-36)

we know sqrt(ab) = sqrt(a) sqrt(b)

x = ±sqrt(36) sqrt(-1)

we know that sqrt (-1) = i

x = ± 6i

3

step-by-step explanation:

because where the point where the 2 lines intersect is (3,-1) the x value is 3