A company supplying candy to school vending machines needs to know about candy preferences of middle school and high school age students. A random sample of 400 students was taken. The company wants to know if there is any relationship between the candy choices and the age of students. After performing a chi-square test of independence, the chi-square test statistic = 24.68. The appropriate critical value for df and desired alpha level = 11.34. Is there sufficient evidence to reject the null hypothesis? Explain.

(x3 + 6x2 + 2x - 6) • (x - 1)

step-by-step explanation:

polynomial long division :

3.2     polynomial long division

dividing :   x4+5x3-4x2-8x+6

                              ("dividend")

by         :     x-1     ("divisor")

dividend     x4   +   5x3   -   4x2   -   8x   +   6

- divisor   * x3     x4   -   x3            

remainder         6x3   -   4x2   -   8x   +   6

- divisor   * 6x2         6x3   -   6x2        

remainder             2x2   -   8x   +   6

- divisor   * 2x1             2x2   -   2x    

remainder               -   6x   +   6

- divisor   * -6x0               -   6x   +   6

remainder                     0

quotient :   x3+6x2+2x-6   remainder:   0

c

-by-step explanation:

it would be c

∈3,600

step-by-step explanation: