The function f has derivatives of all orders for all real numbers with f(0)=3, f'(0)=-4, f''(0)=2, f'''(0)=1. Let g be the function given by g(x)=x∫0 f(t)dt. What is the third-degree Taylor polynomial for g about x=0?

hello from mrbilldoesmath!

answer:   (7x + 6y) ( 49x^2 - 42xy + 36y^2)

discussion:

in general, the factorization of a^3 + b^3 is

a^3 + b^ 3 = (a + b) ( a^2 - ab + b^2)

in our case note that 343 = 7^3 and 216 = 6^3 so the equation becomes:

343x^3 + 216y^3 = (7x)^3 + (6y)^3

if you think of a (above) as 7x and b as 6y the factorization becomes

343x^3 + 216y^3 =

((7x + 6y) (   (7x)^2 - 7x*6y + (6y)^2)   =

(7x + 6y) ( 49x^2 - 42xy + 36y^2)

you,

mrb

(a + b) (a^2 - a b + b^2)

my name jeff

step-by-step explanation:

natural disasters at one point james charles' career

p - 6

step-by-step explanation

so you know that it cost $6 to see a movie you subtract p - 6 to get your answer

hope this !