The weight of oranges growing in an orchard is normally distributed with a mean weight of 7 oz. and a standard deviation of 1 oz. Using the empirical rule, what percentage of the oranges from the orchard weigh between 4 oz. and 10 oz.?

x =±sqrt(1/3)

step-by-step explanation:

x+4/6x=1/x

multiply each side by 6x to get rid of the fractions

6x*(x+4/6x)=1/x*6x

distribute

6x^2 +4 = 6

subtract 4 from each side

6x^2 +4-4 = 6-4

6x^2 =2

divide by 6

6x^2/6 = 2/6

x^2 = 1/3

take the square root of each side

sqrt(x^2) = ±sqrt(1/3)

x =±sqrt(1/3)

definitely a. the others have almost all data points on one side of the line.

step-by-step explanation:

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step-by-step explanation: