What is the perimeter of a quadrilateral with vertices at (1,5), (6,5), (1,11), and (6,11)? Enter the answer in the box.

answer: y=0 if that is what u r looking for

step-by-step explanation:

given that ab is divided into equal parts as

ac, cd, de, ef, fg, gh, hi, ib.

from this we find that f is the midpoint of ab.

so using mid point formula we find

f = (3,7)

similarly considering fb, we get

h = mid point of fb = ((6,6) and g, mid point of fh is

g = (9/2, 13/2)

i is mid point of hb

so i =(15/2,11/2)

i think the answer is c sorry if it's wrong