Find the solution(s) of the following equation. b^2 = 49b
2
=49b, squared, equals, 49
Choose all answers that apply:
Choose all answers that apply:

(Choice A)
A
b = 7b=7b, equals, 7

(Choice B)
B
b = -7b=−7b, equals, minus, 7

(Choice C)
C
b = \sqrt{49}b=
49
​
b, equals, square root of, 49, end square root

(Choice D)
D
b = -\sqrt{49}b=−
49
​
b, equals, minus, square root of, 49, end square root

(Choice E)
E
None of the above

dont think so

step-by-step explanation:

for the friend request.

when a figure, such as triangle (xyz) is reflected over the line y = x to create x'y'z' the x-coordinates and y-coordinates of the original image (pre-image) will be reversed for the image. (e.g., (x, y) > (y, x)) this means that the pre-image position of the x- and y-coordinates switch places which in turn provides a mirror like image of the original xyz.  

i notice that when i draw a line segment from x to x', that the points are parallel from each other -- they are exactly across from each other and do not intersect with any other points.  

yes, think i would see the same characteristic if you drew the line segment connecting y with the reflecting line and then y' with the reflecting line because of the essence of reflections. because it is a mirror image, each point was effected the same way which leads me to conclude that they same would apply to y and y'.

what i would say the best answer is a. 40.5