There are 5 red, 7 orange and 8 blue tickets in a bowl. What are the odds against selecting a red ticket?

1/4

Step-by-step explanation:

first find the total # of tickets: 5 + 7 + 8 = 20

# of red tickets / total: 5/20

remember to always simplify proportion fractions; 5/20 = 1/4

hope that helps! <3

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step-by-step explanation:

hello from mrbilldoesmath!

answer:

25x^2 + 90x + 84

discussion:

mn(x) = m(n(x)) = m( 5x + 9) =

(5x + 9)^2 + 3 =>

25x^2 + 90x + 9^2 + 3 =

25x^2 + 90x + 84                 (as 9^2 = 9*9 = 81)

which is the second choice

regards,  

mrb

p.s.   i'll be on vacation from friday, dec 22 to jan 2, 2019. have a great new year!