Consider g (x) = StartFraction 4 x + 9 Over x Superscript 6 Baseline + 1 EndFraction Which statement correctly uses limits to determine the end behavior of g(x)? Limit of StartFraction 4 x + 9 Over x Superscript 6 Baseline + 1 EndFraction as x approaches plus-or-minus infinity = limit of StartFraction 4 Over 1 EndFraction as x approaches plus-or-minus infinity, so as x approaches infinity, g (x) approaches 4. Limit of StartFraction 4 x + 9 Over x Superscript 6 Baseline + 1 EndFraction as x approaches plus-or-minus infinity = limit of StartFraction 4 Over x Superscript 5 EndFraction as x approaches plus-or-minus infinity, so as x approaches infinity, g (x) approaches 4. Limit of StartFraction 4 x + 9 Over x Superscript 6 Baseline + 1 EndFraction as x approaches plus-or-minus infinity = limit of StartFraction 4 Over x Superscript 5 EndFraction as x approaches plus-or-minus infinity, so as x approaches infinity, g (x) approaches 0. Limit of StartFraction 4 x + 9 Over x Superscript 6 Baseline + 1 EndFraction as x approaches plus-or-minus infinity = limit of StartFraction 4 x Over 1 EndFraction as x approaches plus-or-minus infinity, so as x approaches infinity, g (x) approaches infinity.