Mathematics, 05.05.2021 03:20 Drea1385

The hyperbolic cross section of a cooling tower is given by the equation 4x^2-y^2 + 16y-80 = 0. The center of the cooling tower is the same as the center of the hyperbola, and the x-axls represents the ground surface. The diameter at the center of the tower is () meters. The center of the tower is () meters above the ground. Please help, taking semester exam and need help badly!!!

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The hyperbolic cross section of a cooling tower is given by the equation 4x^2-y^2 + 16y-80 = 0. The...

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