A football is thrown into the air. The height, h(t), of the ball, in metres, after t seconds is modelled by h(t) 4.9(t1.25)29. 1.How high off the ground was the ball when it was thrown?
2.What was the maximum height of the football?
3.How high was the ball at 2.5s?
4.Is the football in the air after 6s?
5.When does the ball hit the ground?

6 hours 48 min

step-by-step explanation:

68÷5=13.6

13.6×30=408min=6 hours 48 min.

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step-by-step explanation:

b. 18

step-by-step explanation:

so the equation for this is:

ab^2=ac⋅ad

ab being the top length of 6 and ac being the length of 2 and ad being the length of x. let's plug into the equation:

6^2 = 2x

now lets just solve for x:

36 = 2x

18 = x

i hope that !

whew you’re speaking a different language