Question 3 of 40 James is given the diagram below and asked to prove that 2D & ZF. What
would be the missing step of the proof?
Given: DEFE, and Ed forms the angle bisector of ZDEF.
Prove: ZD a ZF
E
D
Reasons
Given
Statements
1. DEFE, EO forms the angle
Disctor of ZDEF
2.
3. ΕΟ ΕΟ
4. ADEO NAREO
5. ZDRZE
Definition of an angle bisector
Reflexive Property of Equality
SAS Congruency Theorem
Corresponding parts of congruent
triangles are congruert
Ο Α. ΕΟ: ΕΟ
O B. ED= EF
O C. DOBO
O D. EO = EF

given that triangle abc is transformed two times to get triangle

a"b"c"

first abc is transformed in to a'b'c' as follows:

the coordinates of a are (1,-1) and transformed into a'(-1,1)

similarly b (4,-2) became b'(-4,2) and

c(7,-2) became c'(-7,2)

i.e. (x,y) becomes (-x,-y)

this is nothing but reflection about a point here origin.

thus first transformation is reflection on the origin.

next is exactly shifting 3 units down

source:

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slope= 1

y-inter slope= 0

x       y

o     0

1       1

2     2

ect.

step-by-step explanation:

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step-by-step explanation: