4,12,20 find the 41st term

The 41st term of the given series is 324

Step-by-step explanation:

a= 4

a2= 12

d= a2-a

d= 12-4 = 8

now, we have to find 41 term that is a41

a41 = a+ 40d

a41= 4+ 40× 8

a41= 4+ 320

= 324

therefore the 41st term is 324

324

Step-by-step explanation:

The sequence observed appears to be an arithmetic sequence. The formula for an arithmetic sequence is an = a1 + (n - 1)d, where an is the nth term, a1 is the first term, n is the term position, and d is the common difference. Let's write down what we know.

n = 41

a1 = 4

d = 8

So, let's plug our values into the equation and solve.

an = 4 + (41 - 1)8

an = 4 + (40)8

an = 4 + 320

an = 324

4x and 6y

im not sure though