One card is drawn from a standard 52-card deck and then replaced, and then a second card is drawn. What is the probability that the first card is a red 8 and the second is a
black 10?

1/676

Step-by-step explanation:

In a deck of cards there are 2 red 8's ( 8 of diamonds and 8 of hearts)

P( red 8)  = number of red 8's/ total

               = 2/52 = 1/26

Then we put the card back so there are still 52 cards

In a deck of cards there are 2 black 10's ( 10 of spades and 10 of clubs)

P( black)  = number of black 10's/ total

               = 2/52 = 1/26

Multiply the probabilities together

P( red 8, black 10) = 1/26 * 1/26 = 1 /676

the answer is d on edge

step-by-step explanation:

isocolese triangle

we know that the line connect a and b is the hyptonuse

so first find the hypotonuse length using the distance formula, call the length c

since it is an isocolese triangle, the lengths of the legs are the same

using pythagorean theorem,

in this case, a=b since isocolese triangle so we get

or

we can find c so we can find the distances

we know that if we draw 2 circles, each has center at a and b, and find where they intersect, we can the 2 possible locations for c

if a has center at (xa,ya) and b has center at (xb,yb), then we can solve where

and

intersect to find where they intersect

i'm not going to put an example because i have to go to class. i hope this explanation is enough