Let
X
X
represent the full height of a certain species of tree. Assume that
X
X
has a normal probability distribution with a mean of 55.9 ft and a standard deviation of 5.8 ft.
A tree of this type grows in my backyard, and it stands 62.9 feet tall. Find the probability that the height of a randomly selected tree is as tall as mine or shorter.
P
(
X
<
62.9
)
P
(
X
<
62.9
)
=
My neighbor also has a tree of this type growing in her backyard, but hers stands 72.1 feet tall. Find the probability that the full height of a randomly selected tree is at least as tall as hers.
P
(
X
>
72.1
)
P
(
X
>
72.1
)
=
Enter your answers as decimals accurate to 4 decimal places.
7x the number of visitorsex. 3 visitors would be 7 x 3 =21$ total
Answer from: Quest
1,2,4,5,10,11,20,22,44,55,110,220
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