Find the zeros of the functions
f(x)=(x-2)(x+24)
f(x)=3x(x+1)+5(x-1)

Given: f(x) = 2x + 5 and g(x) = x2 and h(x) = -2x h(g(f( = x2+ vx+ x + y

Prove that the sum of two consecutive exponents of the number 5 is divisible by 30.if two consecutive exponents are 5n and 5n + 1, then their sum can be written as 30.

5/6+7/8what is the answer sealsdbdbshd