If F=2xyz 1-x j -y^2 k, evaluate ∭v F dv, where v is the region bounded by the surface X=0,y=0,X=2,y=6,z=x^2,z=4
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help me to get a solution please ​

option 2 is correct.

step-by-step explanation:

we are given two inequality equation

x+y> 5 and -3x+2y< -2

first we draw the graph of both function using t-table method

equation: x+y> 5

for x=0, y=5

for x=-5, y=0

table:

x   :   0     5

y   :   5     0

test point (0,0) , 0> 5

false

equation: -3x+2y< -2

for x=0, y=-1

for x=2, y=4

table:

x   :   0     2

y   : -1       4

test point (0,0) , 0< -2

true

now we draw the graph. see the attachment for graph.

common region would be solution set.

option 2 is correct.

f(x) = y

f(-3) = -5

step-by-step explanation: