Find the surface area of the net of a square pyramid. Formulas:

A=s2 A = bh A = 12h(b1+b2) A= lw A=12bh
SA = s2 +4(12bh)
SA = 2Lw + 2wh + 2Lh

choice:
180 cm2

144 cm 2

72 cm2

216 cm2

the answer is a

step-by-step explanation:

because if you put 1 in to the square root of x it equals 300.

a 270° rotation about point p says on e d g e n u it y (had to space it out because it says it's a misspelling so i couldn't submit it

answer: (c) m∠qpo + (2x + 16)° = 180°

step-by-step explanation:

the opposite angles of a quadrilateral are supplementary.

so, ∠o + ∠q = 180°   and   ∠p + ∠r = 180°

since ∠r = 2x + 16°, we can use substitution as follows:

∠p + ∠r = 180°

∠p + (2x + 16)° = 180°

where is the diagram? shown below where? ?

step-by-step explanation: