. The world population was 2560 million people in 1950 and 3040 million in 1960 and can be modeled by the function, p(t) = 2560(3)0.17185t where t is time in years after 1950 and p(t) is the population in millions. Determine which interval has the larger average rate of change, from Osts 4 or from 4sts 8 or. Justify your answer, only an algebraic solution will be accepted.​

1 number

if we use a graphing calculator, there is only one such number that satisfies the conclusion of the mean value theorem, that is, a number such that

where the right-hand side is the average rate of change of f on the interval [0.5,0.75], which is the slope of the secant line.

in the attached graph, the black line is the secant line which has its slope as the average rate of change of f on [0.5,0.75], while the orange line is the only tangent line to the graph of f in the interval that satisfies the mvt conclusion.

step-by-step explanation:

b segment jm is correct i think

12 dolars one is cheaper becasue 3 pairs is 6 means is sock is 2 while the 12 is cheaper