a skydiver jumps out from the plane at 10,000 feet above the ground. the skydiver decends at a rate of 175 feet per seconds. how high in the air is the skydiver when he opens his parachute after 25 seconds?

5625 feet

I hope it's helps you

5625 feets

Step-by-step explanation:

Rate(feet/seconds) = height(feets)/time(seconds)

175 = x/25

x = 4375

After the skydiver opens his parachute the height reduces

Initial height – reduced height

10000 – 4375

= 5625 feets

(x3 + 6x2 + 2x - 6) • (x - 1)

step-by-step explanation:

polynomial long division :

3.2     polynomial long division

dividing :   x4+5x3-4x2-8x+6

                              ("dividend")

by         :     x-1     ("divisor")

dividend     x4   +   5x3   -   4x2   -   8x   +   6

- divisor   * x3     x4   -   x3            

remainder         6x3   -   4x2   -   8x   +   6

- divisor   * 6x2         6x3   -   6x2        

remainder             2x2   -   8x   +   6

- divisor   * 2x1             2x2   -   2x    

remainder               -   6x   +   6

- divisor   * -6x0               -   6x   +   6

remainder                     0

quotient :   x3+6x2+2x-6   remainder:   0

v = 1/3 a^2h

step-by-step explanation:

the volume is 1/3 a^2h.