—MUST ANSWER IF YOU KNOW—- Three forces F, F2 and Fz are acting on a body of mass 2 kg such that
F, = (61 - 7j) N,
F2 = (ai +2j) N.
F3 = (5i + bj)
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where a, b are constants.
a) Given that the acceleration of the body is (71 - 3j) ms-2, find the values of the
constants a, b.
[4]
b) A fourth force, F4, is then applied to the body causing it to move with constant
velocity. Find F4, giving your answer in vector form.
[2]

not enough information

step-by-step explanation:

we cannot know this, because the other students could have handed out 10 flyers, or they could have handed out 100. one way, the mean would go up, and another way, the mean would go down.

answer: bearing in mind that a rectangle has a perimeter of length + length + width + width.

step-by-step explanation:

p = perimeter

l = length

x=width

p = 2l + 2x

p = 2(l+x)     < ==== perimeter of the base of the box.

exactly you go it

step-by-step explanation:

answer: cos [   arcsin (3/5) - arccos (1/2) ] =

step-by-step explanation: × = 3/5 = 0.6--> x = 36.87 and x = 180 - 36.87 = 143.13 deg

cos y = 1/2 --> y = +- 60 deg a. cos (x - y) = cos (143.13 - 60) = cos 83,13  

=

0.12

b. cos (36.87 - 60) = cos (-23.23) = 0.92