Solve for 2. =
с
E
3
ro
HI
A
10
B1 D
1/8
AABC and AADE both have a right angle and share BAC.
2/8
Therefore AABC and AADE are similar triangles,
3/8
Therefore, the ratio AB : BC is equal to the ratio AD : DE.
4/8
10
АВ: ВС
-
30

< xcy ≅ < xby

step-by-step explanation:

in δcax and δbax,

so, δcax ≅ δbax (side-angle-side or sas)

since δcax ≅ δbax, we can conclude < acx ≅ < abx

in δacy and δaby,

so, δacy ≅ δaby (side-angle-side or sas)

since δacy ≅ δaby, we can conclude < acy ≅ < aby

now,

< acy ≅ < aby

=> < acx + < xcy ≅ < abx + < xby

=> < acx + < xcy ≅ < acx + < xby   (since < acx ≅ < abx already proved above)

subtracting < acx from both sides, we get

< acx + < xcy -< acx ≅ < acx + < xby -< acx

cancelling out < acx and -< acx from both sides, we get

< xcy ≅ < xby (proved)

the answer for your question is

step-by-step explanation:

22

step-by-step explanation:

22

i think this is a open ended question but i agree with other guy who said you should ask it at english section