A ray and a line intersect to forn 21 and 22 as shown below. If m<1 = (3x+22° and m/2 = (2x+8, what is the measure of <1?

112

68

58

30

step-by-step explanation:

there is a formula i can give you:

it is r^2*n*sin(360/n) divided by 2 where r represents the "radius" and n is the number of sides.

plug them in:

(10sqrt(3))^2*6*sin(360/6) divided by 2

100*3*6*sin(60) divided by 2

900*sin(60)

900*sqrt(3)/2

450*sqrt(3)

approx is 779.4 cm^2

the answer is z7+8/5