Find the 96th term of the arithmetic sequence 1, -12, -25, ...

The 96th term of the arithmetic sequence is -1234.

Step-by-step explanation:

first term (a)=1

second term (t2)=-12

common difference (d)= t2-a

d=-12-1

d=-13

96th term (t96)=?

We know that,

t96=a+(n-1)d

t96=1+(96-1)(-13)

t96=1+95(-13)

t96=1-1235

t96=-1234

step-by-step explanation:

i could only see the first page. the other pages were blurry. ; -;

x hot dogs for 2$, y drinks for 3$. 29 items and total 70

2x+3y=70

x+y=29

if x=17and y=12

2(17)+3(12)=70

34+36=70

1. 3.4/4

2. 0.8/7

3. 0.5 x 3

4. 0.9 x 6

5. 10.8

6. 2.35

7. 0.567

8. 9.35

9. 0.02

10. 0.06

11. 0.16

12. 0.42

13. 0.63

14. 5.6

15. 8.1

16. 9.9

17. 0.28

18. 0.48

19. 0.27

20. 0.49

21. 0.45

22. 0.72

23. 0.9

24. 0.88

25. 0.75

26. 0.16

27. 0.328

28. 0.495

29. 0.72

30. 1.068