Please help me I've been asking for this question for a while and I keep getting those spam messages please help me 15pts How would you go about finding the confidence interval of say 90% or 95% for any given distribution scenario?​

You'd want to divide.

Step-by-step explanation:

Let's say you got a 9/10 on a test.

You'd do 9 divided by 100 and multiply it by 10 to get 90%

That is how you solve a percentage problem

FORMAT IN LESS DETAILED EXPLANATION:

9/100x10=90%

Nine divided by one-hundred times ten equals ninety percent

x= -3 and

step-by-step explanation:

to find the roots of a cubic, use division or factoring to find the factors then set equal to 0. as this is a difference of cubes, it factors into

where a is the cube root of .

here   this is 27 and the cube root of 27 is 3. so we write using the form:

.

set each factor to 0 and solve for x.

x-3=0

x=3

the quadratic expression does not factor and must be solved using the quadratic formula.

where a = 1, b=3, and c=9

this cubic has two complex roots.