Solve using the quadratic formula 1

Step-by-step explanation:

Unless we set x^2 + 8x + 15 equal to zero, we don't have an equation to be solved.  I will assume that the problem is actually x^2 + 8x + 15 = 0.

The coefficients of this quadratic are {1, 8, 15}, and so the "discriminant" b^2 - 4ac is (8)^2 - 4(1)(15), or 4.  Because the discriminant is positive, we know that there are two real, unequal roots.

Continuing with the quadratic formula and knowing that the discriminant is 4, we get:

      -8 ± √4           -8 ± 2

x = = , or x = -2 ± 1:  x = -3 and x = -5

          2                       2

answer: integers are just whole numbers: positive, negative, and zero.

i = {-∞, -2, -1, 0, 1, 2, 3, ∞}

let x = 1st integer

let y = 2nd integer

x = 3y + 17   {equation 1}

xy = -24         {equation 2}

substitute 3y+17 in place of x n equation 2

and solve for y.

(3y+17)y = -24

3y2 + 17y = -24

3y2 + 17y + 24 = 0

from quadratic equation:

y = [-17±√(172-4(3)(24))]/(2(3))

y = (-17 ±√1)/6

y = (-17+1)/6   or     y = (-17-1)/6

y = -16/6           or     y = -18/6

y = -2 2/3         or   y = -3

since we are dealing with

y = -3

x = 3y+17 = -9+17 = 8

the integers are -3, 8

step-by-step explanation:

answer: i ! the answer is   9000 seconds, also d

hope i

-lavira : )