A firework is launched from a platform above the ground and follows the path of the equation below where h=height in feet and t=time in seconds H(t)=-16 squared +64t +40

How long did it take the firework to reach it maximum height (Round to the nearest whole number)?

What was the highest point the firework reached?

How long was the firework in the air. (Round to the tenths place.)

What was the initial height of the firework?

-50/3 is the final answer! : )

step-by-step explanation:

once you graph it hit 2nd (the blue button) and graph

that takes you to a table of coordinates

on the left is x coordinates and on the right is y coordinates and an empty box

(you may have to scroll up/down in order to get ( x, 0)

answer:  

step-by-step explanation:

here x represents the height of the pole,

and, the height of the shadow of the pole is 12 feet.

also, the angle of elevation from the top of the pole is 40°,

therefore,

by the low of sine,

which is the required equation for finding the value of x,

the answer is b.

step-by-step explanation:

by the trigonometric ratio tangent, tangent equals opposite divided by adjacent.

therefore, tan(50) equals ac/3

multiply each side by 3 to get: ac=3tan(50)

the answer is b.