James invests $5,072 in a savings account with a fixed annual interest rate of 9%
compounded continuously. What will the
account balance be after 11 years?

$13087.92

Step-by-step explanation:

formula: ab^x

a= starting  amount

a= 5072

b= 1+r

r=rate

r=9%=0.09

b=1+0.09 =1.09

x= 11 (years)

account after 11 years:

= 5072(1.09)^11

=13087.9227277

= 13087.92

a) y = -3x +2

b) y = 1/2x -6

these 2 can be combined into one equation.

-3x +2 = .5x -6

8 = 3.5x

x = 8 / 3.5 = 2.2857142857

y = -3 * (8 / 3.5) +2

y = (-24 / 3.5) + 2

y = -4.8571428571

step-by-step explanation:

5+2x=a

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