Out of 100 people sampled, 32 had children. Based on this, construct a 90% confidence interval for the true population proportion of people with children. Preliminary:
Is it safe to assume that
n
≤
5
%
n
≤
5
%
of all people with children?
Yes
No

Verify
n
ˆ
p
(
1
−
ˆ
p
)
≥
10
.
n
p
^
(
1
-
p
^
)
≥
10
.
Round your answer to one decimal place.
n
ˆ
p
(
1
−
ˆ
p
)
=
n
p
^
(
1
-
p
^
)
=

Confidence Interval: What is the 90% confidence interval to estimate the population proportion? Round your answer to three decimal places.

<
p
<
<
p