Solving the following system using the elimination method. 2x+y=-9
2x-5y=-3

y=-1 and x=-4

Step-by-step explanation:

2x+y=-9

and

2x-5y=-3

Multiply the second equation by -1, now we have

2x+y=-9

and

-2x+5y=3

Now you can add both sides of the equations and the x values will cancel, because they are opposites (2x and -2x)

2x+y-2x+5y=-9+3

6y=-6

y=-1

We now know y is -1, so we can substitute back into one of our original equations

2x+y=-9

2x+(-1)=-9

2x=-8

x=-4

y is -1 and x is -4

what is the starting amount? the question is not clear sorry.

step-by-step explanation:

f(x) = x^3 -2x^2 -3x

x( x^2 -2x-3)

x( x^2 +x -3x -3)

x( x(x+1) -3(x+1))

x( x-3)( x+1)

so zeroes are 0, 3,-1

its (2) option