A rocket is launched from a tower. The height of the rocket, y in feet, is related to the time after launch, x in seconds, by the given equation. Using this equation, find the
maximum height reached by the rocket, to the nearest tenth of a foot.
y = -16x2 + 125x + 147

The maximum height of the rocket is about 391.1 feet.

Step-by-step explanation:

The height of the rocket y in feet x seconds after launch is modeled by the equation:

We want to find the maximum height reached by the rocket.

Since this is a quadratic equation, the maximum height occurs at the vertex. The vertex of a quadratic is given by:

In this case, a = -16, b = 125, and c = 147.

Thus, the x-coordinate of our vertex is:

To find the maximum height, we will substitute this value back in. So:

The maximum height of the rocket is about 391.1 feet.

the distance between point a and point b is 6 units

answer:   14

step-by-step explanation:          

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