Y = -5/3x +3 and Y = 1/3x -3

(X , Y) = (3 , -2)

Step-by-step explanation:

Assuming this is solved via the comparison method ...

-5/3x+3 = 1/3x-3 which gets you x = 3

Now, substitute the given value of x into the equation, y=1/3x-3(-3)

Solve for Y, Y=-2

The possible solution of the system is the ordered pair (X , Y)

(3 , -2)

< coa = 150 ( given)

as ba and bc are tangents

so oc and oa is perpendicular to cb and ab respectively because in circle normal passes through centre

so in quadrilateral oabc

< coa + < oab + < ocb + < abc = 360

150 +90+90 + < abc = 360

330 + < abc = 360

< abc = 360 -330 = 30

so < abc = 30

⭐dhruv⭐

the answer to question 1 is -8, 28.

step-by-step explanation: