Solve each problem.
1
A biologist is studying diseases in chimpanzees. He takes three random samples of the same
size from a troop of 150 chimpanzees. One sample indicates that 3% of the chimpanzees are
hairless, another sample indicates that 5% are hairless, and a third sample indicates that 4% are
hairless. How many hairless chimpanzees should the biologist expect to find in the troop?

2
A gym teacher fills a basket with 70 balls. Some of the balls are rubber, and the rest are foam.
He has four cļasses per day. Each class gets out 10 balls at random. At the end of class, they put
the balls back in the basket for the next class to use. The first class pulls out 2 rubber balls and 8
foam balls. The second class pulls out 4 rubber balls and 6 foam balls. The third and fourth classes
both pull out 3 rubber balls and 7 foam balls. About how many of the balls in the basket are rubber?
xt Predictions: On

it is c, trust i got your back lol

step-by-step explanation:

step-by-step explanation:

part a. the differences are decreasing, so we know the sequence is not arithmetic. the ratios are constant (=3/4), so we know the sequence is geometric.

part b. from part a, we know the common ratio is 3/4, so each term is 3/4 of the one before. the initial term is the number of gallons at h=1.

g[h] = (3/4)·g[h-1]

g[1] = 384 . . . . initial value required for a recursive definition

part c. the general formula for a geometric sequence is

a[n] = a[1]·r^(n-1)

we have a[1] = 384, r = 3/4, and the term number given by h. the formula that follows is

g[h] = 384·(3/4)^(h-1)

part d. filling in the value and doing the arithmetic, we have

g[12] = 384·(3/4)^11 ≈ 384·0.042235136 ≈ 16.2183 . . gallons

part e. each gallon is 4 quarts, so

16.2183 gal × 4 qt/gal = 64.8732 qt

b. ol

step-by-step explanation:

i got the answer right on edg.

congruent: (geometry) (of figures) identical in form; coinciding exactly when superimposed.