What are the real or imaginary solutions of the polynomial equation -6x^5 + 21x 4-9x^3+33x^2-18x = 6x^4 + 3x^3 + 3x^2 + 6x?​

answer rather than having to add and subtract the measurements of the semi-circle, notice that the semicircle to the left of ad is actually identical in area to the blank semicircle-shaped space to the left of bc. so if we transferred the red semicircle into the blank space, we would end up with a square of side length 24 cm. the area of a square is s^2 = 24^2 = 676 cm^2.

u also answered this so i think u would know but i am here to

put in or use mine

i believe the answer is 68cm

step-by-step explanation:

i just took 34 x 2 because the space between v and y is the same as y to k.

y=1/4x-4

step-by-step explanation:

step-by-step explanation:

circumference divided by 3.141592654 then timesthe radius twice