1/2 minus 2/3
I have trouble with fractions ​

-1/6

Step-by-step explanation:

Hope this helps down below! Pls mark brainliest

Multiply both the numerator and denominator of each fraction by the number that makes its denominator equal the LCD. This is basically multiplying each fraction by 1.

(12×33)−(23×22)=?

Complete the multiplication and the equation becomes

36−46=?

The two fractions now have like denominators so you can subtract the numerators.

Then:

3−46=−16

This fraction cannot be reduced.

Therefore:

12−23=−16

Solution by Formulas

Apply the fractions formula for subtraction, to

12−23

and solve

(1×3)−(2×2)2×3

=3−46

=−16

Therefore:

12−23=−16

-1/6

Step-by-step explanation:

the answer to this is a. a^2 + b^2 = c^2

1. when "a" is a root of a polynomial, (x -a) is a factor of it. for the three roots given, the factors of the desired polynomial are (x +2)(x -1/2)(x -3).

in order to make the leading coefficient be negative, we need to multiply this product by a negative number. any negative number will do, but we choose a small (magnitude) value that will eliminate the fraction: -2.

then

f(x) = -2(x +2)(x -1/2)(x -3) = -(x +2)(2x -1)(x -3)

= -(2x² +3x -2)(x -3)

= -(2x³ -3x² -11x +6)

f(x) = -2x³ +3x² +11x -6

2. a graph created by the desmos on-line graphing calculator is shown, and the zeros are highlighted.

3. as indicated in part 1, the multiplier of this equation can be anything and the zeros will remain the same. you want a negative leading coefficient, so the "anything" is restricted to any of the infinite number of numbers that will make that be the case.