Please put your exact answers in bold. Thank you! A random sample of 40 adults with no children under the age of 18 years results in a mean daily leisure time of 5.17 ​hours, with a standard deviation of 2.49 hours. A random sample of
40 adults with children under the age of 18 results in a mean daily leisure time of 4.18
​hours, with a standard deviation of 1.99
hours. Construct and interpret a 95​%
confidence interval for the mean difference in leisure time between adults with no children and adults with children μ1−μ2.
Let μ1 represent the mean leisure hours of adults with no children under the age of 18 and
μ2 represent the mean leisure hours of adults with children under the age of 18.

The 95​% confidence interval for μ1−μ2
is the range from hours to hours.
​(Round to two decimal places as​ needed.)

What is the interpretation of this confidence​ interval?

A.
There is a
95​%
probability that the difference of the means is in the interval. Conclude that there is a significant difference in the number of leisure hours.

B.
There is a
95​%
probability that the difference of the means is in the interval. Conclude that there is insufficient evidence of a significant difference in the number of leisure hours.

C.
There is
95​%
confidence that the difference of the means is in the interval. Conclude that there is
a
significant difference in the number of leisure hours.

D.
There is
95​%
confidence that the difference of leisure hours.