If C = 3t-1+t^6 and D = 2t + 7, find an expression that equals 2C - 2D in standard form.​

1/3x+ 5 = -2x - 2

Step-by-step explanation:

Step-by-step explanation:

C = 3t - 1 + t^6

D = 2t + 7

2C - 2D

2(3t - 1 + t^6) - 2(2t + 7)

6t -2 + 2t^6 - 4t - 14

2t^6 + 2t - 16

ab: 2 n83b8eb7ebi. 8e yen in

for the friend request.

when a figure, such as triangle (xyz) is reflected over the line y = x to create x'y'z' the x-coordinates and y-coordinates of the original image (pre-image) will be reversed for the image. (e.g., (x, y) > (y, x)) this means that the pre-image position of the x- and y-coordinates switch places which in turn provides a mirror like image of the original xyz.  

i notice that when i draw a line segment from x to x', that the points are parallel from each other -- they are exactly across from each other and do not intersect with any other points.  

yes, think i would see the same characteristic if you drew the line segment connecting y with the reflecting line and then y' with the reflecting line because of the essence of reflections. because it is a mirror image, each point was effected the same way which leads me to conclude that they same would apply to y and y'.