What is the probability of drawing two yellow marbles if the first one is NOT placed back into the bag before the second draw?

2/10 on the first draw and 1/9 on the second draw

Step-by-step explanation:

In the first draw, 2 marbles are yellow out of 10, but on the second draw, you don't replace a yellow marble leaving 1 yellow marble out of 9 total marbles in the bag.

the correct answer to your question is a. 4^4

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step-by-step explanation:

x^(1/6) · x^(1/6) · x^(1/6)   ·x^(1/6) = x^(4/6)   since we add the exponents

4/6 can be simplified to 2/3

the simplified form is x^(2/3)