GIVING BRAINLIEST TO THE CORRECT ANSWER!! Marta's dog just had six puppies. Four are female (F), and two are male (M). One of the males is brown. Two of the females are brown. All puppies are either brown or white. If Marta randomly gives away puppies to her friends, what is the probability of a friend getting a puppy that is male, brown, or both?

4. What is the probability that a puppy Marta gives away is male, brown, or both? Explain.​

Step-by-step explanation:

No of total brown = 2 + 1 = 3 .

probability = 3 / 6

= 1 /2 .

no of males = 2

probability

= 2 / 6

= 1 /3

no of person who is both male and brown = 1

probability = 1 /6

Required probability

= probability of being brown + probability of being male - probability of being both

= 1 / 2 + 1 / 3 - 1 /6

= 4 / 6

= 2 / 3 .

2/9 I think

Step-by-step explanation:

If there are two brown females and one brown male those are exact. Then there are 3 more puppies that can be any color. So you add up all the posibilities wich is 9 and then there are two possibilities that they will be male AND brown. So 2/9 I think

step-by-step explanation:

first, eliminate the parenthesis:

3

x

+

2

−

4

x

second, group like terms:

3

x

−

4

x

+

2

third, combine like terms:

(

3

−

4

)

x

+

2

→

−

1

x

+

2

→

−

x

+

2