The diagram shows a logo. ABE and DCE are congruent triangles.
BCE is a sector of a circle, centre E.
Show that the area of the logo is 460 cm?
to 2 significant figures.
B.
C
CE2=142+272-2(27)(14)cos(32)=283.87 56393
CE=16.85
area of sector=105/360**16.852=260.158
tariangle=1/2(14(17)sin32=100.154 100.154*2=200.31
200.31+260.1=460

tube or goog would be a great resource to with that question

center (1,3) with radius 6

step-by-step explanation:

we must complete the square to find the center and radius of the circle.

first make sure the x and y squared terms have 1 as their coefficients. we also make sure x and y terms together.

we now create space between the x and y terms with parenthesis.

we complete the square by taking the middle terms -2x and the -6y - divide each and square them.

we add the squares to both sides.

simplify.

and write the quadratics in factored form.

the center is (h,k) or (1,3). the radius is the square root of 36 which is 6.

lo98765432wqasdfghjkloi87654567890

step-by-step explanation:

the polynomial is a perfect square trinomial of the form a^2-2ab+b^2:

option a. true

step-by-step explanation:

9x^2-12x+4

comparing with the form a^2-2ab+b^2

1.) a^2=9x^2

solving for a: square root both sides of the equation:

sqrt(a^2)=sqrt(9x^2)

a=sqrt(9) sqrt(x^2)

a=3x

2.) b^2=4

solving for b: square root both sides of the equation:

sqrt(b^2)=sqrt(4)

b=2

to be a perfet square trinomial 2ab must be equal to 12x. let's check:

2ab = 2 (3x) (2)

2ab = 12x

correct