A rocket is launched from a tower. The height of the rocket, y in feet, is related to the time after launch, x in seconds, by the given equation. Using this equation, find the maximum height reached by the rocket, to the nearest tenth of a foot. y=−16x^2+146x+137

10.17

Step-by-step explanation:

Given the following Quadratic equation:

The steps to solve it are:

1. Substitute  into the equation:

2. Use the Quadratic formula .

In this case:

Substituting values into the Quadratic equation, you get (Round the values to the nearest hundreth):

3. The positive value is the time that the rocket will hit the ground.

Therefore, the rocket will hit the ground after .

22.83 repeating

step-by-step explanation:

137 ÷ 6 is 22.8333333 therefore we understand that 3 is repeating.

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