In ARST, r = 86 inches, s = 77 inches and T=9º. Find the area of ARST, to the nearest square inch.

When graphing the two equations, the point of intersection is the solution. *by the way the top question is an example of the graph* to graph each equation, apply the slope intercept form, y = mx + b *find solution for all* equations: 1) y = 5x - 2 y = x + 6 2) y = 2x - 4 y = x +2 3) y = x + 2 y = -x +2 now for questions 4-6, check the solution too 4) y = 3x + 2 y = 3x - 4 m= m= b= b= 5) y = 2x + 1 2y = 4x + 2 m= m= b= b= 6) y = x - 3 y = -x +3 m= m= b= b= *dont have to check solution for 7-9* 7) y = 5x + 1 y = x - 3 8) y = x - 5 y = 3x + 1 9) y = 3x - 1 y = 3x - 4

Acircular garden with radius of 8 feet is surrounded by a circular path with a width of 3 feet. what is the approximate area of the path alone? use 3.14 for π

5/6+7/8what is the answer sealsdbdbshd