A postcard has an area of 6 square inches. Two enlargements of the postcard have areas of 24 square inches and 96 square inches. In each postcard, the length is 1 1
2
times the width.

Which of the following could be the dimensions of the postcard or one of the enlargements? Mark all that apply.

A 4 inches by 12 inches
B 2 inches by 3 inches
C 3 inches by 8 inches
D 8 inches by 12 inches
E 4 inches by 6 inches

51-50

step-by-step explanation:

37/3

step-by-step explanation:

step 1: simplify both sides of the equation.

7x+8(x+

1

4

)=3(6x−9)−8

7x+(8)(x)+(8)(

1

4

)=(3)(6x)+(3)(−9)+−8(distribute)

7x+8x+2=18x+−27+−8

(7x+8x)+(2)=(18x)+(−27+−8)(combine like terms)

15x+2=18x+−35

15x+2=18x−35

tep 2: subtract 18x from both sides.

15x+2−18x=18x−35−18x

−3x+2=−35

step 3: subtract 2 from both sides.

−3x+2−2=−35−2

−3x=−37

step 4: divide both sides by -3.

−3x

−3

=

−37

−3

x=

37

3