Sin(theta/2) =1/2 , : Write an equation that expresses the value of theta/2 in terms of an appropriate inverse trigonometric expression.
: Write an equation that expresses the value of(0,2pi)

in terms of an appropriate inverse trigonometric expression theta/2.

Part III: On the interval
(0,2pi)
, what values of
theta
does your answer to Part II produce?

im pretty sure its

(8,15)

step-by-step explanation:

3 qrs + 3/2 xy hope this : /

step-by-step explanation:

the correct option is:

b. a value of the variable that makes the polynomial equal to zero.

the root or roots of a polynomial are the values of the variable that makes the polynomial equal to 0. we can find the roots of a polynomial making the expression equal to 0 and then, isolating the variable (it it has just one variable).

for example, given the following polynomial:

the root or zero of the polynomial, can be found by making the expression equal to 0, and then, isolating the variable, so, finding the root we have:

therefore, we have that the root of the polynomial is equal to 2.

we must remember that the number of roots that a polynomial can have, will depend on the degree of the polynomial, a first degree polynomial have will have one single root, a second degree polynomial (quadratic expression) may have two roots and so.

hence the correct option is:

b. a value of the variable that makes the polynomial equal to zero.

have a nice day!