If AB = 9 units, QS = 6 units, and AR = QR = RS, what is the area of the heart shape?

Step-by-step explanation:

AR = QR = RS  = (1/2) QS  = 3

So by the Pythagorean Theorem, AS = AQ  =

√ [3^2  + 3^2]   =  √[9 + 9 ]  = √18  

And the area of the two  semi-circles= the area of a circle with a radius of AS/2 =  

pi [AS/2]^2 =

pi [√18/2]^2  =  18pi/4  =  (9/2)pi  units^2

And the area of the rest of the figure is just that of a rhombus  =

The product of the diagonals / 2   =

AB*QS/2  = 9 * 6 / 2  = 27 units^2

Sothe total area  =

[(9/2) pi + 27]   units^2   =  about  =  41.1 units^2  [rounded]

1. 3. can also be expressed as (22/7)

2. -4.5

3. 3.6

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22.83 repeating

step-by-step explanation:

137 ÷ 6 is 22.8333333 therefore we understand that 3 is repeating.

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