Write \displaystyle y = −x^2 + 12x − 5y=−x2+12x−5 into the form \displaystyle y = a(x − h)^2 + k. y=a(x−h)2+k. GIVEN that h =h=\frac{-b}{2a}2a−b​ and k=k= \fra c{4ac-b^{2}}{4a}4a4ac−b2​

then hh= kk=

FINALLY yy= (x-x− )^{2}2++

Write \displaystyle y = −x^2 + 12x − 5y=−x2+12x−5 into the form \displaystyle y = a(x − h)^2 + k. y=a(x−h)2+k.

GIVEN that h =h=\frac{-b}{2a}2a−b​ and k=k= \fra c{4ac-b^{2}}{4a}4a4ac−b2​

then hh= kk=

FINALLY yy= (x-x− )^{2}2++​

step-by-step explanation:

we are given

since, we have to isolate x on anyone side

so, we can move all x terms on one side

subtract both sides by 2x

add both sides by 9

divide both sides by 4

we get

percentage - 25%

probability - 0.25

we know,

total amount of students in class = 20

total boys = 10

total girls = 10

no of girls who wear glasses = 10/2 = 5

probability of choosing a girl with glasses is =

number of girls wearing glasses/total number of students in the class = 5/20

thus, percentage of selecting a girl wearing glasses will be

= 5/20 × 100

= 5 × 5

25%

therefore,

probability will be 0.25

happy to

pls mark as brainliest