PLEASE HELP ME I'll give you brainliest points! Given: \overline{AB} \parallel \overline{DC}
AB
∥
DC
and EE is the midpoint of \overline{AC}.
AC
.

Prove: \triangle ABE \cong \triangle CDE△ABE≅△CDE.
Step Statement Reason
1
\overline{AB} \parallel \overline{DC}
AB
∥
DC

EE is the midpoint of \overline{AC}
AC

Given

1. minimum

2. 6400

3. eight

hope this !

ƒ = 0.03b

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step-by-step explanation:

12 cups   is the answer

step-by-step explanation:

place r′ so that qr′ is parallel to the tangent.

now we get that ∠r′py=∠pr′q, where y is on the tangent, on the opposite side of p from x.

also, because of the symmetry, ∠r′py=∠qpx.

finally, note that no matter where we place r, as long as it's on the correct arc, we have ∠prq=∠pr′q.

stringing all these equalities together, we end up with ∠prq=∠qpx.

this picture will show how its going to look like.

hope this by jack monhen