A classic physics problem states that if a projectile is shot vertically up into the
air with an initial velocity of 162 feet
per second from an initial height of 117
feet off the ground, then the height of
the projectile, h, in feet, t seconds after
it's shot is given by the equation:
h = – 16t2 + 162t + 117
Find the two points in time when the
object is 160 feet above the ground.
Round your answers to the nearest
hundredth of a second (two decimal
places)

3x^3-x^2+6x-9

b. 6

step-by-step explanation:

we are given the table representing an exponential function.

we can see from the table that, as x is increasing, the value of y is increasing in the power of 6.

i.e. the following relation is obtained,

x = 1, y = 6

x = 2, y = 36 =

x = 3, y = 216 =

x = 4, y = 1296 =

x = 5, y = 7776 =

so, the geometric series obtained is .

thus, the common ratio is given by = = 6.

hence, the common ratio is 6.

, and

for

step-by-step explanation:

we can analyze the pattern at which the terms increase. let us denote , , , so that we can call

note the following:

the pattern: to get the next term value, we just add the next term number (e.g. 1st, 2nd, to the previous term value (term values are the given numbers in the question, 1, 3, 6, 10, 15,

from , to get to , we add

from , to get to , we add

etc.

we need to form a recursive formula, a formula that has the next term as a function of the previous term. so a possible recursive formula can be

, and for

the correct answer is $7.38

step-by-step explanation: